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3(x^2-72x-288)=0
We multiply parentheses
3x^2-216x-864=0
a = 3; b = -216; c = -864;
Δ = b2-4ac
Δ = -2162-4·3·(-864)
Δ = 57024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{57024}=\sqrt{5184*11}=\sqrt{5184}*\sqrt{11}=72\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-216)-72\sqrt{11}}{2*3}=\frac{216-72\sqrt{11}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-216)+72\sqrt{11}}{2*3}=\frac{216+72\sqrt{11}}{6} $
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